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Lesson 11 — Trigonometric ratios in the right triangle

Sine, cosine and tangent as ratios between sides of the right triangle. From Babylon (1800 BC) to the GPS in your phone.

Used in: 1st year HS · Basic physics (vectors) · Surveying

sinθ=opp. leghypotenuse,cosθ=adj. leghypotenuse,tanθ=sinθcosθ\sin\theta = \frac{\text{opp. leg}}{\text{hypotenuse}}, \quad \cos\theta = \frac{\text{adj. leg}}{\text{hypotenuse}}, \quad \tan\theta = \frac{\sin\theta}{\cos\theta}
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Rigorous notation, full derivation, hypotheses

Rigorous definition

θa (opposite)b (adjacent)c (hypotenuse)ACB

Right triangle. Sine = opposite/hypotenuse, cosine = adjacent/hypotenuse, tangent = opposite/adjacent. SOH-CAH-TOA mnemonic: Sin = Opposite/Hypotenuse, Cos = Adjacent/Hypotenuse, Tan = Opposite/Adjacent.

Why do the ratios depend only on the angle?

Thales' theorem (similarity): triangles with the same angles are proportional. So the ratio a/ca/c is the same in any right triangle with angle θ\theta — independent of size.

Fundamental identity

(1)
what this means · Pythagorean identity. Comes directly from a² + b² = c² (Pythagoras), dividing both sides by c²: (a/c)² + (b/c)² = 1, that is, sin²θ + cos²θ = 1.

Notable values

θ\thetasinθ\sin\thetacosθ\cos\thetatanθ\tan\theta
30°30°1/21/23/2\sqrt{3}/23/3\sqrt{3}/3
45°45°2/2\sqrt{2}/22/2\sqrt{2}/211
60°60°3/2\sqrt{3}/21/21/23\sqrt{3}

These values must be memorized. They come from 3030-6060-9090 and 4545-4545-9090 (isosceles) triangles.

Proof — 45-45-90 triangle

An isosceles right triangle has equal legs (a=ba = b). By Pythagoras: c=a2c = a\sqrt{2}. So:

sin45°=aa2=12=22,cos45°=22,tan45°=1\sin 45° = \frac{a}{a\sqrt{2}} = \frac{1}{\sqrt 2} = \frac{\sqrt 2}{2}, \quad \cos 45° = \frac{\sqrt 2}{2}, \quad \tan 45° = 1

Exercise list

50 exercises · 12 with worked solution (25%)

Application 18Understanding 12Modeling 15Challenge 3Proof 2
  1. Ex. 11.1ApplicationAnswer key

    In a right triangle, the acute angle θ\theta has opposite leg 3 and adjacent leg 4. Compute sinθ,cosθ,tanθ\sin\theta, \cos\theta, \tan\theta.

  2. Ex. 11.2ApplicationAnswer key

    A right triangle has legs 5 and 12. Compute the hypotenuse and sin,cos,tan\sin, \cos, \tan of the angle opposite to leg 5.

  3. Ex. 11.3ApplicationAnswer key

    Hypotenuse = 13 and leg opposite to θ\theta equals 5. Compute sinθ\sin\theta and cosθ\cos\theta.

  4. Ex. 11.4Application

    Compute exact sin30°\sin 30°, cos30°\cos 30°, tan30°\tan 30°.

    Solve onlineref: OpenStax A&T §8.1
  5. Ex. 11.5Application

    Compute exact sin60°\sin 60°, cos60°\cos 60°, tan60°\tan 60°.

  6. Ex. 11.6ApplicationAnswer key

    Compute exact sin45°\sin 45°, cos45°\cos 45°, tan45°\tan 45°.

  7. Ex. 11.7Application

    If sinθ=3/2\sin\theta = \sqrt{3}/2 and θ\theta is acute, what is θ\theta?

  8. Ex. 11.8Application

    If cosθ=1/2\cos\theta = 1/2 and θ\theta is acute, what is θ\theta?

  9. Ex. 11.9Application

    If tanθ=1\tan\theta = 1 and θ\theta is acute, what is θ\theta?

  10. Ex. 11.10Application

    In a 30°30°-60°60°-90°90° triangle with hypotenuse 10, compute the legs.

  11. Ex. 11.11Application

    If sinθ=3/5\sin\theta = 3/5 and θ\theta is acute, compute cosθ\cos\theta.

    Solve onlineref: Stitz-Zeager §10.2
  12. Ex. 11.12Application

    If cosθ=5/13\cos\theta = 5/13 and θ\theta is acute, compute sinθ\sin\theta and tanθ\tan\theta.

  13. Ex. 11.13Application

    If tanθ=2/3\tan\theta = 2/3 and θ\theta is acute, compute sinθ\sin\theta and cosθ\cos\theta.

  14. Ex. 11.14Understanding

    Verify the identity sin230°+cos230°=1\sin^2 30° + \cos^2 30° = 1 using the notable values.

  15. Ex. 11.15UnderstandingAnswer key

    Show that tanθ=sinθ/cosθ\tan\theta = \sin\theta / \cos\theta from the right-triangle definitions.

  16. Ex. 11.16Understanding

    Show that sin(90°θ)=cosθ\sin(90° - \theta) = \cos\theta from the right triangle.

  17. Ex. 11.17Understanding

    For acute θ\theta, which is greater: sin60°\sin 60° or cos60°\cos 60°? Why?

  18. Ex. 11.18Understanding

    Show that sinθ<1\sin\theta < 1 for every acute θ\theta. (Use the triangle inequality.)

  19. Ex. 11.19Understanding

    For acute θ1,θ2\theta_1, \theta_2 with θ1<θ2\theta_1 < \theta_2: show that sinθ1<sinθ2\sin\theta_1 < \sin\theta_2 (sine is increasing on [0,90°][0, 90°]).

  20. Ex. 11.20Understanding

    Show that tanθ+\tan\theta \to +\infty when θ90°\theta \to 90°^-.

  21. Ex. 11.21Application

    In a right triangle with hypotenuse 20 cm and acute angle 35°35°, compute the legs. (Use sin35°0.574\sin 35° \approx 0{.}574 and cos35°0.819\cos 35° \approx 0{.}819.)

  22. Ex. 11.22ApplicationAnswer key

    Opposite leg = 6, angle θ=40°\theta = 40°. Compute the hypotenuse. (Use sin40°0.643\sin 40° \approx 0{.}643.)

  23. Ex. 11.23Application

    Adjacent leg = 10, angle θ=25°\theta = 25°. Compute the opposite leg. (Use tan25°0.466\tan 25° \approx 0{.}466.)

  24. Ex. 11.24Application

    Hypotenuse = 25, opposite leg = 7. Compute the angle θ\theta. (Ans: arcsin(7/25)16.26°\arcsin(7/25) \approx 16{.}26°.)

  25. Ex. 11.25Application

    Legs 8 and 15. Compute the two acute angles.

  26. Ex. 11.26UnderstandingAnswer key

    In an equilateral triangle of side \ell, compute the height using trigonometry. Compare with the result from Pythagoras.

  27. Ex. 11.27Understanding

    In a square of side \ell, compute the diagonal using trigonometry.

  28. Ex. 11.28Understanding

    Show that sinθ+cosθ=2sin(θ+45°)\sin\theta + \cos\theta = \sqrt{2} \sin(\theta + 45°) using angle addition. (Preview Lesson 12.)

  29. Ex. 11.29UnderstandingAnswer key

    In a right triangle with adjacent leg bb and hypotenuse cc, express tanθ\tan\theta in terms of bb and cc.

  30. Ex. 11.30Understanding

    Compute (without calculator) sin75°\sin 75°. (Hint: 75°=45°+30°75° = 45° + 30°. Use the sum formula — look it up if needed.)

  31. Ex. 11.31Modeling

    A 5 m ladder is leaning against the wall forming a 70°70° angle with the ground. At what height does it touch the wall?

    Solve onlineref: OpenStax A&T §8.4
  32. Ex. 11.32ModelingAnswer key

    You are 50 m from the base of a tower. The angle of elevation to the top is 40°40°. What is its height?

  33. Ex. 11.33Modeling

    A plane takes off and reaches 1,500 m altitude horizontally 5 km from the runway. What is the climb angle?

  34. Ex. 11.34Modeling

    A ship observes a lighthouse 200200 m tall under an angle of elevation of 3°. How far is the ship from the lighthouse?

  35. Ex. 11.35ModelingAnswer key

    An accessibility ramp has a maximum slope of 5° (NBR 9050). To overcome 80 cm of height, what is the minimum length of the ramp?

  36. Ex. 11.36Modeling

    In a solar eclipse, the Moon has angular diameter 0.5°0{.}5° seen from Earth. Real diameter: 3,474 km. Compute the Earth-Moon distance. (Use tan(0.25°)0.004363\tan(0{.}25°) \approx 0{.}004363.)

  37. Ex. 11.37ModelingAnswer key

    A 200 N force is applied to a body in a direction forming 30°30° with the horizontal. Compute the horizontal and vertical components of the force.

  38. Ex. 11.38Modeling

    A 50 kg block is on a 20°20° ramp. What is the force parallel to the ramp that tends to make the block slide? (g=10g = 10 m/s².)

  39. Ex. 11.39Modeling

    The Eiffel Tower is 324 m tall. At what angle do you see the top if you are 500 m from the base?

  40. Ex. 11.40Modeling

    A drone is 100 m high and detects a person on the ground at a 30°30° angle below the horizon (depression). Horizontal distance drone-person?

  41. Ex. 11.41Modeling

    A surveyor is at a point AA and measures the top of a hill at an angle of 25°25°. He walks 100 m toward the hill to BB and the angle becomes 40°40°. Compute the height of the hill. (System of two equations.)

  42. Ex. 11.42ModelingAnswer key

    A steel cable supports a 30 m antenna fixed to the ground 12 m from the base. What is the length of the cable? What is the angle of the cable with the ground?

  43. Ex. 11.43Modeling

    In a 1 m pendulum, the wire forms a 15°15° angle with the vertical at the extreme. What is the height of the extreme above the equilibrium point?

  44. Ex. 11.44Modeling

    GPS computes your position using angles to 4 satellites. Simplified 2D model: two satellites at (0,20,000)(0, 20{,}000) km and (15,000,25,000)(15{,}000, 25{,}000) km see you under angles α,β\alpha, \beta with the vertical. (Sketch, do not solve — visualize triangulation.)

  45. Ex. 11.45Modeling

    A road makes a V-curve with 8%8\% ascent followed by 5%5\% descent. Compute the angles of ascent and descent in degrees.

    Solve onlineref: ENEM-style
  46. Ex. 11.46Challenge

    Show that in a right triangle with angles θ\theta and 90°θ90° - \theta, we have sinθcosθ=sin(θ)cos(90°θ)/2\sin\theta \cdot \cos\theta = \sin(\theta) \cos(90° - \theta)/2. (More general: sin(2θ)=2sinθcosθ\sin(2\theta) = 2\sin\theta\cos\theta.)

  47. Ex. 11.47Challenge

    In a right triangle, show that area =12c2sinθcosθ= \frac{1}{2} c^2 \sin\theta \cos\theta where cc is the hypotenuse and θ\theta one of the acute angles.

  48. Ex. 11.48Challenge

    Solve: sinθ+cosθ=1\sin\theta + \cos\theta = 1 for θ[0°,90°]\theta \in [0°, 90°].

  49. Ex. 11.49Proof

    Prove sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1 using the right triangle and Pythagoras.

  50. Ex. 11.50Proof

    Show that sinθ=cos(90°θ)\sin\theta = \cos(90° - \theta) for every θ(0°,90°)\theta \in (0°, 90°).

Sources for this lesson

Only books that directly fed the text and the exercises. General catalog at /livros.

  • Algebra and Trigonometry — Jay Abramson et al. (OpenStax) · 2022, 2nd ed · EN · CC-BY · §8.1-8.4: trigonometric ratios, Pythagorean identities, applications. Primary source for blocks A-D.
  • Precalculus / College Algebra / Trigonometry — Carl Stitz, Jeff Zeager · 2013, v3 · EN · CC-BY-NC-SA · §10.2-10.3: acute-angle trigonometry. Source for block B.
  • College Trigonometry — Stitz, Zeager · 2013 · EN · CC-BY-NC-SA · ch. 10: extensive treatment and exercises.
  • Geometria e Trigonometria — Wikibooks · live · PT-BR · CC-BY-SA · reference in Portuguese.
  • University Physics (Volume 1) — OpenStax · 2016 · EN · CC-BY · ch. 2: vectors and decomposition. Source for block D (modeling in physics).

Updated on 2026-04-29 · Author(s): Clube da Matemática

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