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Lesson 25 — Conics: ellipse, parabola, hyperbola

The three conics and their canonical equations. Focus-directrix, eccentricity. Applications in planetary orbits and antennas.

Used in: 1.º ano EM (15–16 anos) · Equiv. Math II japonês §II.4 · Equiv. Klasse 11 alemã Analytische Geometrie

x2a2+y2b2=1,y2=4px,x2a2y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1, \qquad y^2 = 4px, \qquad \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1
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Rigorous notation, full derivation, hypotheses

Canonical equations

Ellipse

Sum of distances to 2 foci is constant: x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1

Where a>b>0a > b > 0. Foci at (±c,0)(\pm c, 0) with c=a2b2c = \sqrt{a^2 - b^2}. Major axis =2a= 2a, minor =2b= 2b. Eccentricity e=c/a[0,1)e = c/a \in [0, 1). When a=ba = b, it is a circle.

Parabola

Distance to focus == distance to directrix: y2=4pxy^2 = 4px

Focus at (p,0)(p, 0), directrix x=px = -p.

Hyperbola

Difference of distances to 2 foci is constant: x2a2y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1

Foci at (±c,0)(\pm c, 0) with c=a2+b2c = \sqrt{a^2 + b^2}. Eccentricity e=c/a>1e = c/a > 1. Asymptotes y=±(b/a)xy = \pm (b/a) x.

Table of the three conics

ConicCanonical equationEccentricityFocus(es)Definition
Circlex2+y2=r2x^2 + y^2 = r^2e=0e = 0centerdist. to center =r= r
Ellipsex2/a2+y2/b2=1x^2/a^2 + y^2/b^2 = 10<e<10 < e < 1(±c,0)(\pm c, 0)r1+r2=2ar_1 + r_2 = 2a
Parabolay2=4pxy^2 = 4pxe=1e = 1(p,0)(p, 0)r=r = dist. to directrix
Hyperbolax2/a2y2/b2=1x^2/a^2 - y^2/b^2 = 1e>1e > 1(±c,0)(\pm c, 0)r1r2=2a\|r_1 - r_2\| = 2a

General form of a conic

Ax2+Bxy+Cy2+Dx+Ey+F=0Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0

Discriminant Δ=B24AC\Delta = B^2 - 4AC:

  • Δ<0\Delta < 0: ellipse (or circle if A=C,B=0A=C, B=0).
  • Δ=0\Delta = 0: parabola.
  • Δ>0\Delta > 0: hyperbola.

Exercise list

35 exercises · 8 with worked solution (25%)

Application 20Modeling 12Challenge 2Proof 1
  1. Ex. 25.1Application
    Identify the conic: x2/9+y2/4=1x^2/9 + y^2/4 = 1. (Ans: ellipse.)
  2. Ex. 25.2Application
    Vertices of the ellipse x2/25+y2/16=1x^2/25 + y^2/16 = 1. (Ans: (±5,0)(\pm 5, 0) and (0,±4)(0, \pm 4).)
  3. Ex. 25.3ApplicationAnswer key
    Eccentricity of the ellipse x2/25+y2/9=1x^2/25 + y^2/9 = 1. (Ans: 4/54/5.)
  4. Ex. 25.4Application
    Focus of the parabola y2=8xy^2 = 8x. (Ans: (2,0)(2, 0).)
  5. Ex. 25.5Application
    Directrix of y2=12xy^2 = 12x.
  6. Ex. 25.6Application
    Asymptotes of x2/4y2/9=1x^2/4 - y^2/9 = 1. (Ans: y=±32xy = \pm \frac{3}{2}x.)
  7. Ex. 25.7Application
    Identify: x2/16y2/9=1x^2/16 - y^2/9 = 1.
  8. Ex. 25.8Application
    Equation of the ellipse with vertices (±5,0)(\pm 5, 0) and focus (±3,0)(\pm 3, 0).
  9. Ex. 25.9Application
    Equation of the parabola with vertex at the origin and focus at (2,0)(2, 0).
  10. Ex. 25.10Application
    Equation of the hyperbola with vertices (±4,0)(\pm 4, 0) and focus (±5,0)(\pm 5, 0).
  11. Ex. 25.11Application
    The ellipse 4x2+9y2=364x^2 + 9y^2 = 36 — vertices? (Ans: (±3,0),(0,±2)(\pm 3, 0), (0, \pm 2).)
  12. Ex. 25.12Application
    Sketch y2=4xy^2 = 4x and mark focus and directrix.
  13. Ex. 25.13ApplicationAnswer key
    x2/16+y2/16=1x^2/16 + y^2/16 = 1 — which conic? (Ans: circle r=4r=4.)
  14. Ex. 25.14ApplicationAnswer key
    The ellipse x2/9+y2/16=1x^2/9 + y^2/16 = 1 has its major axis in which direction? (Ans: vertical.)
  15. Ex. 25.15ApplicationAnswer key
    Length of the major axis of the ellipse 4x2+25y2=1004x^2 + 25y^2 = 100. (Ans: 10.)
  16. Ex. 25.16Application
    Verify whether (3,0)(3, 0) is on the ellipse x2/9+y2/4=1x^2/9 + y^2/4 = 1.
  17. Ex. 25.17ApplicationAnswer key
    For which aa is it true that x2/a2+y2/16=1x^2/a^2 + y^2/16 = 1 has eccentricity 0.60.6? (Ans: a=5a = 5.)
  18. Ex. 25.18Application
    The parabola y2=4xy^2 = 4x intersects x=4x = 4 at which points? (Ans: (4,±4)(4, \pm 4).)
  19. Ex. 25.19ApplicationAnswer key
    Hyperbola x2y2=1x^2 - y^2 = 1 — vertices, foci, asymptotes.
  20. Ex. 25.20Application
    Sketch x2/4+y2=1x^2/4 + y^2 = 1.
  21. Ex. 25.21Modeling
    Earth's orbit: semi-major axis a1.496×108a \approx 1.496 \times 10^8 km, e0.0167e \approx 0.0167. Maximum Sun-Earth distance (aphelion)?
  22. Ex. 25.22ModelingAnswer key
    Satellite TV parabolic antenna: depth 30 cm, aperture 60 cm. Where is the focus?
  23. Ex. 25.23Modeling
    Ballistic trajectory: h(d)=0.05d2+5dh(d) = -0.05 d^2 + 5d. Parabolic shape — vertex (max range)?
  24. Ex. 25.24Modeling
    Halley's comet has an elliptical orbit with eccentricity e0.967e \approx 0.967. Almost parabolic — explain.
  25. Ex. 25.25Modeling
    Elliptical-shaped skate park: 20m × 12m. Equation of the ellipse.
  26. Ex. 25.26Modeling
    Reflecting telescope: focus 2 m from the parabolic mirror. Equation y2=42xy^2 = 4 \cdot 2 \cdot x — aperture for 1m diameter?
  27. Ex. 25.27Modeling
    Kitchen parabolic infrared cooker: focus on infrared ray. Focus-vertex distance 15 cm. Equation.
  28. Ex. 25.28Modeling
    LORAN (GPS predecessor) uses hyperbolas. Conceptually: why do 2 receivers define 1 hyperbola?
  29. Ex. 25.29Modeling
    U.S. Capitol has an elliptical ceiling — a whisper at one focus is heard at the other. For a 20m×12m20m \times 12m chamber, distance between foci?
  30. Ex. 25.30Modeling
    The Voyager 1 probe passed by Jupiter on a hyperbolic trajectory. What is the importance of e>1e > 1 for the swing-by?
  31. Ex. 25.31Modeling
    In optimization, contours of f(x,y)=x2/4+y2/9f(x, y) = x^2/4 + y^2/9 are concentric ellipses. Direction of the gradient?
  32. Ex. 25.32Modeling
    2019 Nobel Prize in Physics (nobelprize.org): exoplanets in elliptical orbits around other stars. Typical eccentricity?
  33. Ex. 25.33Challenge
    Reflection in an ellipse: a ray from focus 1 arrives at focus 2. Use this to design a "whisper chamber".
  34. Ex. 25.34Challenge
    For a general conic Ax2+Bxy+Cy2+Dx+Ey+F=0Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0, the discriminant B24ACB^2 - 4AC classifies it: <0< 0 ellipse, =0= 0 parabola, >0> 0 hyperbola. Verify for canonical cases.
  35. Ex. 25.35ProofAnswer key
    Derive the canonical equation of the ellipse from the definition PF1+PF2=2a|PF_1| + |PF_2| = 2a.

Sources

Updated on 2026-04-30 · Author(s): Clube da Matemática

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