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Lesson 28 — Applications of Vectors in Physics

Forces, displacement, velocity, acceleration. Decomposition on a ramp. Static equilibrium.

Used in: 1.º ano do EM (16 anos) · Equiv. Physik Klasse 10 alemã · Equiv. Physics I japonês · H2 Physics singapurense

Fi=ma\sum \vec{F}_i = m \vec{a}
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Rigorous notation, full derivation, hypotheses

Vectors in mechanics

Fundamental principles

  1. Static equilibrium: Fi=0\sum \vec F_i = \vec 0 (object at rest or in uniform rectilinear motion).
  2. Newton's 2nd law: Fi=ma\sum \vec F_i = m \vec a.
  3. Decomposition: for a ramp of inclination θ\theta, gravity g=gȷ^\vec g = -g\hat\jmath projects to gsinθ-g\sin\theta parallel (downhill) and gcosθ-g\cos\theta normal.

Work and energy

  • Work: W=FdW = \vec F \cdot \vec d.
  • Power: P=FvP = \vec F \cdot \vec v.
  • Kinetic energy: K=12mv2K = \frac{1}{2} m |\vec v|^2.
  • Work-energy theorem: Wtotal=ΔKW_{\text{total}} = \Delta K.

Vector kinematics

  • Position: r(t)\vec r(t).
  • Velocity: v(t)=dr/dt\vec v(t) = d\vec r/dt.
  • Acceleration: a(t)=dv/dt\vec a(t) = d\vec v/dt.

For uniformly accelerated motion: r(t)=r0+v0t+12at2\vec r(t) = \vec r_0 + \vec v_0 t + \frac{1}{2} \vec a t^2

Classical forces

ForceExpressionNotes
WeightP=mg\vec P = m\vec galways vertical, downward
NormalN\vec N \perp surfacereaction to compression
Frictionf=μNf = \mu Nopposes motion
TensionTT along the cableequal at both ends (ideal cable)
SpringF=kx\vec F = -k\vec xHooke
CentripetalFc=mv2/rF_c = mv^2/rtoward the center

Equilibrium in 2D

3 independent equations: Fx=0\sum F_x = 0, Fy=0\sum F_y = 0, MO=0\sum M_O = 0 (moment about any point OO).

Exercise list

35 exercises · 8 with worked solution (25%)

Application 20Understanding 1Modeling 10Challenge 3Proof 1
  1. Ex. 28.1ApplicationAnswer key
    Resultant of F1=(3,4)\vec F_1 = (3, 4) N and F2=(1,2)\vec F_2 = (-1, 2) N. (Ans: (2,6)(2, 6) N.)
  2. Ex. 28.2Application
    For equilibrium, F1+F2+F3=0\vec F_1 + \vec F_2 + \vec F_3 = \vec 0 with F1=(5,0)\vec F_1 = (5, 0), F2=(3,4)\vec F_2 = (-3, 4). Compute F3\vec F_3. (Ans: (2,4)(-2, -4).)
  3. Ex. 28.3Application
    Mass of 10 kg on a 30° ramp. Force parallel to the ramp (gravity): mgsin30°mg \sin 30° = ? (Ans: 49 N.)
  4. Ex. 28.4Application
    Mass in free fall: F=(0,mg)\vec F = (0, -mg), a=(0,g)\vec a = (0, -g).
  5. Ex. 28.5ApplicationAnswer key
    Block on a smooth 45° ramp. Acceleration as it slides: gsin45°=g2/2g \sin 45° = g\sqrt 2/2.
  6. Ex. 28.6Application
    Resultant velocity of a boat vb=(0,4)\vec v_b = (0, 4) km/h on a river with current vc=(3,0)\vec v_c = (3, 0) km/h.
  7. Ex. 28.7Application
    Time to cross an 800 m river: depends only on vbȷ^=4\vec v_b \cdot \hat\jmath = 4 km/h. (Ans: 12 min.)
  8. Ex. 28.8ApplicationAnswer key
    Work done by F=(5,3)\vec F = (5, 3) N to displace an object d=(4,0)\vec d = (4, 0) m. (Ans: 20 J.)
  9. Ex. 28.9Application
    Work done by a force perpendicular to displacement: zero.
  10. Ex. 28.10Application
    For a cable pulling F=100\vec F = 100 N at 30° above horizontal on a cart that moves d=(10,0)\vec d = (10, 0) m: W=?W = ? (Ans: 5003866500\sqrt 3 \approx 866 J.)
  11. Ex. 28.11Application
    Average acceleration: a=(vfvi)/Δt\vec a = (\vec v_f - \vec v_i)/\Delta t. For vi=(10,0)\vec v_i = (10, 0), vf=(10,5)\vec v_f = (10, 5), Δt=2\Delta t = 2s: a\vec a? (Ans: (0,2.5)(0, 2.5) m/s².)
  12. Ex. 28.12Application
    Projectile trajectory under a=(0,g)\vec a = (0, -g) with v0=(v0cosθ,v0sinθ)\vec v_0 = (v_0 \cos\theta, v_0 \sin\theta).
  13. Ex. 28.13Application
    Time of flight of a projectile launched at 45° with v0=20v_0 = 20 m/s.
  14. Ex. 28.14ApplicationAnswer key
    Horizontal range of the same projectile.
  15. Ex. 28.15ApplicationAnswer key
    Maximum height of the projectile.
  16. Ex. 28.16Application
    Block on a ramp with friction: friction force f=μN=μmgcosθf = \mu N = \mu mg \cos\theta against motion.
  17. Ex. 28.17Application
    For which θ\theta does the block start to slide (static friction μs=0.3\mu_s = 0.3)? θ=arctanμs\theta = \arctan \mu_s. (Ans: 16.7°\approx 16.7°.)
  18. Ex. 28.18Application
    Unit vector in the direction of motion v=(3,4)\vec v = (3, 4).
  19. Ex. 28.19Application
    Decomposition of (10,0)(10, 0) N along the direction parallel to a 30°30° ramp: 10cos30°10 \cos 30° along, 10sin30°10 \sin 30° normal.
  20. Ex. 28.20Application
    In equilibrium, simple truss: node with 3 forces. Compute tensions.
  21. Ex. 28.21Modeling
    Plane at 800 km/h heading north with 100 km/h east wind. Resultant velocity (magnitude + angle).
  22. Ex. 28.22Modeling
    For the plane above to actually go true north, what heading should it point?
  23. Ex. 28.23ModelingAnswer key
    Inclined plane 20°, mass 5 kg, friction μ=0.25\mu = 0.25. Net parallel force?
  24. Ex. 28.24Modeling
    Tightrope walker, weight W=600W = 600 N. Tension on each side of the rope when it makes a 5° angle with horizontal.
  25. Ex. 28.25Modeling
    Inverted-V truss with 2 cables supporting 1000 kg, each cable at 30°30° from vertical. Tension in each cable.
  26. Ex. 28.26ModelingAnswer key
    Car in a curve: centripetal force Fc=mac\vec F_c = m \vec a_c points toward the center. For 1,000 kg at 60 km/h on a 100 m radius curve: Fc=?F_c = ?
  27. Ex. 28.27Modeling
    Rocket launched at 60° with v0=100v_0 = 100 m/s. Vector trajectory r(t)\vec r(t).
  28. Ex. 28.28Modeling
    Drone with upward thrust Fm=(0,F)\vec F_m = (0, F) against weight P=(0,mg)\vec P = (0, -mg) and horizontal wind V=(V,0)\vec V = (V, 0). Resultant.
  29. Ex. 28.29Modeling
    Electric vehicle on uphill: motor Fm\vec F_m + friction Ff\vec F_f + parallel gravity mgsinθ-mg\sin\theta = mam\vec a.
  30. Ex. 28.30ModelingAnswer key
    In digital games, projectile obeys vector equations — implement update rn+1=rn+vnΔt\vec r_{n+1} = \vec r_n + \vec v_n \Delta t, vn+1=vn+aΔt\vec v_{n+1} = \vec v_n + \vec a \Delta t.
  31. Ex. 28.31Understanding
    Show that a launch angle of 45°45° maximizes the range on a horizontal plane without air friction.
  32. Ex. 28.32Challenge
    Block AA of 10 kg on top of block BB of 20 kg, both on a frictionless surface. F=60F = 60 N is applied horizontally to AA. Acceleration of AA and BB if static friction between them is sufficient.
  33. Ex. 28.33Challenge
    Two cables support a 500 N load. Cable 1 at 30° from vertical, cable 2 at 60°. Tension in each.
  34. Ex. 28.34Proof
    Prove that the centripetal force on an object in uniform circular orbit is F=mv2/rF = mv^2/r.
  35. Ex. 28.35Challenge
    Show that in uniform circular motion, acceleration is perpendicular to velocity.

Sources

Updated on 2026-04-30 · Author(s): Clube da Matemática

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