Home/High School/강 19 — 직관적 극한✓v1 · padrão canônico강 19 — 직관적 극한극한이란? x가 어떤 값에 접근할 때 함수가 접근하는 값. 직관적, ε-δ 없이. 5분기 공식 정의를 위한 그라운드 준비.Used in: 고등학교 1학년 · 미적분 예습(5분기)limx→af(x)=L\lim_{x \to a} f(x) = Lx→alimf(x)=LListen Choose your doorFormal10 yearsRigorous notation, full derivation, hypotheses직관적 정의극한 법칙두 극한이 모두 존재하면:limx→a[f(x)+g(x)]=limx→af(x)+limx→ag(x)\lim_{x \to a} [f(x) + g(x)] = \lim_{x \to a} f(x) + \lim_{x \to a} g(x)limx→a[f(x)+g(x)]=limx→af(x)+limx→ag(x)limx→a[f(x)⋅g(x)]=[limx→af(x)]⋅[limx→ag(x)]\lim_{x \to a} [f(x) \cdot g(x)] = \left[\lim_{x \to a} f(x)\right] \cdot \left[\lim_{x \to a} g(x)\right]limx→a[f(x)⋅g(x)]=[limx→af(x)]⋅[limx→ag(x)]등등.
직관적 정의극한 법칙두 극한이 모두 존재하면:limx→a[f(x)+g(x)]=limx→af(x)+limx→ag(x)\lim_{x \to a} [f(x) + g(x)] = \lim_{x \to a} f(x) + \lim_{x \to a} g(x)limx→a[f(x)+g(x)]=limx→af(x)+limx→ag(x)limx→a[f(x)⋅g(x)]=[limx→af(x)]⋅[limx→ag(x)]\lim_{x \to a} [f(x) \cdot g(x)] = \left[\lim_{x \to a} f(x)\right] \cdot \left[\lim_{x \to a} g(x)\right]limx→a[f(x)⋅g(x)]=[limx→af(x)]⋅[limx→ag(x)]등등.