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第49课 — 序列极限(形式化)

Definição rigorosa de limite de sequência. Convergência, divergência. Bolzano-Weierstrass, Cauchy, monótona limitada.

Used in: 2.º ano do programa (17 anos) · Equiv. Math III japonês cap. 6 · Equiv. Klasse 12 LK Análise alemã · Equiv. H2 Math singapurense — Sequences & Series

limnan=L    ε>0,NN:nNanL<ε\lim_{n \to \infty} a_n = L \iff \forall \varepsilon > 0, \exists N \in \mathbb{N} : n \geq N \Rightarrow |a_n - L| < \varepsilon
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Rigorous notation, full derivation, hypotheses

序列、收敛与定理

关键定理

定理陈述
唯一性极限若存在,唯一
算术lim(an±bn)=liman±limbn\lim(a_n \pm b_n) = \lim a_n \pm \lim b_n
夹逼anbncna_n \leq b_n \leq c_nliman=limcn=Llimbn=L\lim a_n = \lim c_n = L \Rightarrow \lim b_n = L
单调有界上界递增收敛
Bolzano-Weierstrass有界序列有收敛子列
柯西ana_n 收敛     \iff 是柯西

柯西

R\mathbb{R}:柯西     \iff 收敛(完备性)。 Q\mathbb{Q}:并非每个柯西都收敛(ana_n 逼近 2\sqrt 2)。

单调 + 有界

  • (an)(a_n) 递增上界 \Rightarrow 收敛于 supan\sup a_n
  • (an)(a_n) 递减下界 \Rightarrow 收敛于 infan\inf a_n

子序列

(ank)(a_{n_k})(an)(a_n) 的子序列若 n1<n2<n_1 < n_2 < \ldotsliman=L\lim a_n = L \Rightarrow 每个子列 limank=L\lim a_{n_k} = L

发散序列

  • an=(1)na_n = (-1)^n:在 1-111 间振荡。子列收敛(±1\pm 1),但 ana_n 不。
  • an=na_n = n:无界增长(+\to +\infty)。
  • an=nsin(n)a_n = n \sin(n):不规则,无极限。

递归序列

an+1=f(an)a_{n+1} = f(a_n),给定 a0a_0。若极限存在,是 ff不动点L=f(L)L = f(L)

Exercise list

42 exercises · 10 with worked solution (25%)

Application 30Understanding 3Modeling 6Proof 3
  1. Ex. 49.1ApplicationAnswer key
    lim1/n\lim 1/n。用 ε-N 证:对 \eps\epsN=1/\epsN = \lceil 1/\eps \rceil
  2. Ex. 49.2Application
    lim(n+1)/n\lim (n+1)/n。(答:1。)
  3. Ex. 49.3Application
    lim(2n2)/(n2+1)\lim (2n^2)/(n^2 + 1)。(答:2。)
  4. Ex. 49.4Application
    lim(1)n\lim (-1)^n——收敛?
  5. Ex. 49.5Application
    lim(1)n/n\lim (-1)^n/n
  6. Ex. 49.6Application
    limsin(n)/n\lim \sin(n)/n 通过夹逼。
  7. Ex. 49.7Application
    lim(1+1/n)n=e\lim (1 + 1/n)^n = e
  8. Ex. 49.8Application
    limnk/an\lim n^k / a^na>1a > 1。(答:0。)
  9. Ex. 49.9Application
    liman/n!\lim a^n/n!a>0a > 0。(答:0。)
  10. Ex. 49.10ApplicationAnswer key
    limn1/n\lim n^{1/n}。(答:1。)
  11. Ex. 49.11Application
    a1=1,an+1=(an+2/an)/2a_1 = 1, a_{n+1} = (a_n + 2/a_n)/2liman=?\lim a_n = ?(答:2\sqrt 2。)
  12. Ex. 49.12Application
    调和序列 Hn=1+1/2++1/nH_n = 1 + 1/2 + \ldots + 1/n——收敛?
  13. Ex. 49.13ApplicationAnswer key
    limcos(nπ)/n\lim \cos(n\pi)/n。(答:0。)
  14. Ex. 49.14Application
    limn!/nn\lim n!/n^n。(答:0。)
  15. Ex. 49.15Application
    lim(n!)1/n/n\lim (n!)^{1/n}/n。(答:1/e1/e,通过斯特林。)
  16. Ex. 49.16Application
    lim(3n+4n)1/n\lim (3^n + 4^n)^{1/n}。(答:4。)
  17. Ex. 49.17ApplicationAnswer key
    limnsin(1/n)\lim n \sin(1/n)。(答:1。)
  18. Ex. 49.18Application
    lim(lnn)/n\lim (\ln n)/n
  19. Ex. 49.19Application
    lim(n+1n)\lim (\sqrt{n+1} - \sqrt n)。(答:0。)
  20. Ex. 49.20ApplicationAnswer key
    limn(n+1n)\lim n(\sqrt{n+1} - \sqrt n)。(答:1/21/2。)
  21. Ex. 49.21Application
    an+1=2+ana_{n+1} = \sqrt{2 + a_n}a0=1a_0 = 1。证收敛并算 LL。(答:2。)
  22. Ex. 49.22Application
    an+1=(an+3)/2a_{n+1} = (a_n + 3)/2a0=0a_0 = 0。算 LL。(答:3。)
  23. Ex. 49.23Application
    an+1=an2/2a_{n+1} = a_n^2/2a0=1a_0 = 1。收敛?
  24. Ex. 49.24Application
    归一化斐波那契:fn+1/fnφ=(1+5)/2f_{n+1}/f_n \to \varphi = (1+\sqrt 5)/2。证。
  25. Ex. 49.25Application
    an=k=1n1/k2a_n = \sum_{k=1}^n 1/k^2。收敛?(答:是,π2/6\pi^2/6。)
  26. Ex. 49.26ApplicationAnswer key
    an=k=1n1/ka_n = \sum_{k=1}^n 1/k。收敛?(答:否——调和发散。)
  27. Ex. 49.27ApplicationAnswer key
    证递增上界序列是柯西。
  28. Ex. 49.28Application
    an=na_n = n 不是柯西。
  29. Ex. 49.29Application
    an=(1)na_n = (-1)^n 有两个收敛子列(去 111-1)。
  30. Ex. 49.30Application
    an=(1+1/n)n+1a_n = (1 + 1/n)^{n+1}——极限?与 (1+1/n)n(1 + 1/n)^n 之差?
  31. Ex. 49.31Modeling
    5\sqrt 5 牛顿迭代:an+1=(an+5/an)/2a_{n+1} = (a_n + 5/a_n)/2。从 a0=2a_0 = 2a5a_5
  32. Ex. 49.32Modeling
    在 ML 中,梯度下降:wn+1=wnαf\mathbf{w}_{n+1} = \mathbf{w}_n - \alpha \nabla fα<2/L\alpha < 2/LLL Lipschitz 常数)时收敛。
  33. Ex. 49.33Modeling
    连续复利:Vn=V0(1+r/n)nV_n = V_0 (1 + r/n)^nVnV0erV_n \to V_0 e^r——基本极限。
  34. Ex. 49.34Modeling
    离散放射衰变:Nn+1=Nn(1λΔt)N_{n+1} = N_n (1 - \lambda \Delta t)。连续极限。
  35. Ex. 49.35Modeling
    二项 \to 泊松:(nk)pk(1p)nk\binom{n}{k} p^k (1-p)^{n-k}np=λnp = \lambda 固定,nn \to \infty。结果。
  36. Ex. 49.36ModelingAnswer key
    逻辑斯蒂映射 xn+1=rxn(1xn)x_{n+1} = r x_n (1 - x_n)r=2r = 2 算极限。r=3,5r = 3{,}5?(答:4 周期。)
  37. Ex. 49.37Understanding
    用 ε-N 证 lim1/n=0\lim 1/n = 0
  38. Ex. 49.38Understanding
    证单调递增有界收敛。
  39. Ex. 49.39UnderstandingAnswer key
    证每个柯西有界。
  40. Ex. 49.40Proof
    证极限唯一性。
  41. Ex. 49.41ProofAnswer key
    证序列夹逼定理。
  42. Ex. 49.42Proof
    证 Bolzano-Weierstrass:R\mathbb{R} 中有界序列有收敛子列。

参考来源

Updated on 2026-04-30 · Author(s): Clube da Matemática

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