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Lição 92 — EDOs separáveis

dy/dx = g(x)h(y). Separar variáveis e integrar dos dois lados. Aplicações: decaimento radioativo, resfriamento de Newton, crescimento logístico.

Used in: Spécialité Maths francesa (Terminale) · Math III japonês avançado · Leistungskurs Mathematik 12 alemão · H2 Mathematics singapurense

dydx=g(x)h(y)    dyh(y)=g(x)dx+C\frac{dy}{dx} = g(x)\,h(y) \;\Rightarrow\; \int \frac{dy}{h(y)} = \int g(x)\,dx + C
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Rigorous notation, full derivation, hypotheses

严格定义和方法

标准形式和可分离性

"A separable equation is actually the first kind of differential equation that can be solved explicitly." — Lebl, Notes on Diffy Qs, §1.3

奇异解(平衡点)

存在性和唯一性定理(Picard-Lindelöf)

"Theorem 1.2.1. If f(x,y)f(x,y) is continuous and f/y\partial f/\partial y is continuous near some (x0,y0)(x_0, y_0), then a solution exists for xx near x0x_0, and is unique." — Lebl, Notes on Diffy Qs, §1.2

方向场和定性分析

xyy*=0equil.y > 0y < 0

dy/dx = y 的方向场。金色水平等斜线是平衡点 y* = 0。对于 y > 0,解上升;对于 y < 0,解下降——平衡点不稳定

Osgood 准则(全局存在性)

示例: y˙=y2\dot y = y^2y(0)=1y(0) = 11dy/y2=1<\displaystyle\int_1^\infty dy/y^2 = 1 < \infty ——爆破在 T=1T = 1 处。

已解决的示例

Exercise list

45 exercises · 11 with worked solution (25%)

Application 24Understanding 6Modeling 9Challenge 4Proof 2
  1. Ex. 92.1Application

    求解 dydx=5y\dfrac{dy}{dx} = 5y

  2. Ex. 92.2Application

    求解初值问题 dydx=y2\dfrac{dy}{dx} = -\dfrac{y}{2}y(0)=4y(0) = 4

  3. Ex. 92.3Application

    求解 dydx=xy\dfrac{dy}{dx} = xy

  4. Ex. 92.4Application

    求解 dydx=xy\dfrac{dy}{dx} = \dfrac{x}{y}y(0)=2y(0) = 2

  5. Ex. 92.5Application

    求解 dydx=exy\dfrac{dy}{dx} = e^{x-y}

  6. Ex. 92.6Application

    求解 dydx=(1+y2)cosx\dfrac{dy}{dx} = (1 + y^2)\cos x

  7. Ex. 92.7Application

    求解 dydx=x2y\dfrac{dy}{dx} = \dfrac{x^2}{y}y(1)=2y(1) = 2

  8. Ex. 92.8ApplicationAnswer key

    求解 y=yxy' = y\sqrt{x}

  9. Ex. 92.9Application

    求解 dydx=cosxy\dfrac{dy}{dx} = \dfrac{\cos x}{y}

  10. Ex. 92.10ApplicationAnswer key

    求解 dydx=e2xy\dfrac{dy}{dx} = \dfrac{e^{2x}}{y}

  11. Ex. 92.11ApplicationAnswer key

    求解 dydx=2xy2\dfrac{dy}{dx} = -2xy^2

  12. Ex. 92.12Application

    通过部分分式求解 dydx=y21\dfrac{dy}{dx} = y^2 - 1

  13. Ex. 92.13Application

    求解 y=(1y)/xy' = (1-y)/xy(1)=0y(1) = 0

  14. Ex. 92.14Application

    验证 y=11+exy = \dfrac{1}{1+e^{-x}} 求解 y=y(1y)y' = y(1-y)

  15. Ex. 92.15ApplicationAnswer key

    求解 dydx=2x1+y2\dfrac{dy}{dx} = \dfrac{2x}{1+y^2}

  16. Ex. 92.16Application

    求解 ysinx=ycosxy'\sin x = y\cos x

  17. Ex. 92.17Application

    求解 dydx=ytanx\dfrac{dy}{dx} = y\tan xy(0)=1y(0) = 1

  18. Ex. 92.18Application

    求解 yex=yy'\,e^x = y

  19. Ex. 92.19Application

    求解 dydx=yx2\dfrac{dy}{dx} = \dfrac{y}{x^2}y(1)=ey(1) = e

  20. Ex. 92.20Application

    求解 y=1y2y' = \sqrt{1 - y^2}。讨论定义域和奇异解。

  21. Ex. 92.21ModelingAnswer key

    放射性衰变:14{}^{14}C 的半衰期为 5730 年。10000 年后剩余百分之多少?

  22. Ex. 92.22ModelingAnswer key

    RC 电路放电:V(0)=12V(0) = 12 V,R=1kΩR = 1\,\text{k}\OmegaC=100μFC = 100\,\mu\text{F}。求 V(t)V(t)

  23. Ex. 92.23Modeling

    100 L 装满纯水的坦克,每分钟进入 5 L 浓度 10 g/L 的盐水,并排出 5 L/min。30 分钟后浓度是多少?

  24. Ex. 92.24Modeling

    细菌菌落每 3 小时翻倍。增长 100 倍需要多长时间?

  25. Ex. 92.25Modeling

    牛顿冷却定律:20°C 房间里的 90°C 咖啡在 5 分钟后达到 70°C。何时达到 30°C?

  26. Ex. 92.26Modeling

    具有线性阻力的自由落体:v˙=gkv\dot v = g - kvv(0)=0v(0) = 0。求解并确定末端速度 vv_\infty

  27. Ex. 92.27ModelingAnswer key

    药物浓度:C˙=0.1C\dot C = -0.1CC(0)=C0C(0) = C_0。多久降至初始剂量的 50%?

  28. Ex. 92.28Modeling

    投资以年利率 5% 的连续复利增长:S˙=0.05S\dot S = 0.05 S。资本翻倍需要多长时间?

  29. Ex. 92.29UnderstandingAnswer key

    证明 y0y \equiv 0y=y2y' = y^2 的解。它属于一般族吗?证明。

  30. Ex. 92.30Understanding

    对于 y=y2/3y' = y^{2/3}y(0)=0y(0) = 0,证明存在无穷多个解。为什么 Picard 唯一性会失败?

  31. Ex. 92.31UnderstandingAnswer key

    为什么 dyy=lny+C\displaystyle\int \dfrac{dy}{y} = \ln|y| + C 使用绝对值?

  32. Ex. 92.32Understanding

    对于 y˙=y(1y)\dot y = y(1-y),识别平衡点并将其分类为稳定或不稳定。

  33. Ex. 92.33Understanding

    下列哪种形式的 dy/dx=F(x,y)dy/dx = F(x,y) 对应可分离的微分方程?

  34. Ex. 92.34Challenge

    通过替换 u=x+yu = x+y 求解 y=(x+y)2y' = (x+y)^2

  35. Ex. 92.35Challenge

    证明 y˙=y2\dot y = y^2y(0)=y0>0y(0) = y_0 > 0 在有限时间 T=1/y0T = 1/y_0 爆炸。用 Osgood 准则确认。

  36. Ex. 92.36Challenge

    Bernoulli 方程 y+P(x)y=Q(x)yny' + P(x)y = Q(x)y^n。证明替换 u=y1nu = y^{1-n} 将其转换为线性微分方程。

  37. Ex. 92.37Proof

    通过 Picard 迭代为 y=f(x,y)y' = f(x,y)y(x0)=y0y(x_0) = y_0 素描 Picard-Lindelöf 定理的证明,其中 ff 连续且在 yy 中 Lipschitz。

  38. Ex. 92.38ProofAnswer key

    对于 y˙=h(y)\dot y = h(y)h(y)>0h(y) > 0 对所有 yy0y \geq y_0,证明解是全局的当且仅当 y0+dyh(y)=+\displaystyle\int_{y_0}^{+\infty} \dfrac{dy}{h(y)} = +\infty(Osgood 准则)。

  39. Ex. 92.39Application

    求解 dydx=y2ex\dfrac{dy}{dx} = y^2 e^x

  40. Ex. 92.40Application

    通过部分分式求解 dydx=y24\dfrac{dy}{dx} = y^2 - 4。识别奇异解。

  41. Ex. 92.41Application

    求解 dydx=x21+y2\dfrac{dy}{dx} = \dfrac{x^2}{1+y^2}

  42. Ex. 92.42Application

    求解 dydx=eysinx\dfrac{dy}{dx} = e^{-y}\sin x

  43. Ex. 92.43Modeling

    逻辑斯谛增长:P˙=0,06P(1P/500)\dot P = 0{,}06\,P(1 - P/500)P(0)=50P(0) = 50。种群何时达到承载量的一半?

  44. Ex. 92.44UnderstandingAnswer key

    定性分析 y˙=y(2y)\dot y = y(2-y) 而不显式求解:识别平衡点、稳定性和不同初值条件下的解的行为。

  45. Ex. 92.45Challenge

    对于 y˙=yp\dot y = y^py(0)=y0>0y(0) = y_0 > 0,确定 pp 的哪些值导致有限时间爆破。在这种情况下计算 TT

来源

  • Lebl, Notes on Diffy Qs — Jiří Lebl · v6.6 · CC-BY-SA. §1.3 Separable equations; §1.2 Picard-Lindelöf. 本课的主要来源。
  • OpenStax Calculus Volume 2 — OpenStax · CC-BY-NC-SA. §4.3 Separable Equations. 建模示例:牛顿、混合、细菌、药物动力学。
  • APEX Calculus — Hartman et al. · CC-BY-NC. §8.1 Graphical and Numerical Solutions, §8.1 Separable Differential Equations. 定性分析、方向场、Bernoulli。

Updated on 2026-05-06 · Author(s): Clube da Matemática

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